Where E is the energy radiated away from the star in the form of E-M radiation, T is the surface temperature of the star and is a constant known as the Stephan-Boltzmann constant.
This means that if you double the temperature of an object, it will radiate   2 x 2 x 2 x 2 = 16   times as much energy per square unit of area and in total if its surface area doesn't change.
SUN:   1 L ; T = 5500 K Ori:   27,500 L ; T = 3400 K
So, something funny is going on. The Sun has a higher surface temperature so it must radiate more energy per unit surface area. There is only one way that Ori could radiate more total energy - it must have a larger total surface area.
- How much larger is Ori?
for the Sun is larger than that of Ori by :If the two stars had the same radius and surface area, the Sun would radiate 6.8 times as much energy. But Ori has a total energy radiated that is 27,000 times more than that of the Sun.
- We can quantify the difference in the size of the two stars using Stephan's Law.
So the surface area of Ori is 187,000x the surface area of the Sun. This star has a radius (remember area is proportional to r2) which is 432 times larger than the Sun. The star is cool, but large.