| E |
= | x T4 | |
| Area |
Where E is the energy radiated away from the star in the form of E-M radiation, T is the surface temperature of the star and is a constant known as the Stephan-Boltzmann constant.
This means that if you double the temperature of an object, it will radiate   2 x 2 x 2 x 2 = 16   times as much energy per square unit of area and in total if its surface area doesn't change.
SUN:   1 L ![]()
; T = 5500 K Ori:   27,500 L ![]()
; T = 3400 K So, something funny is going on. The Sun has a higher surface temperature so it must radiate more energy per unit surface area. There is only one way that Ori could radiate more total energy - it must have a larger total surface area.
- How much larger is Ori?
If the two stars had the same radius and surface area, the Sun would radiate 6.8 times as much energy. But Ori has a total energy radiated that is 27,000 times more than that of the Sun. for the Sun is larger than that of Ori by :
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- We can quantify the difference in the size of the two stars using Stephan's Law.
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So the surface area of Ori is 187,000x the surface area of the Sun. This star has a radius (remember area is proportional to r2) which is 432 times larger than the Sun. The star is cool, but large.
to nearly
1000 R
.